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Automating and Programming Cisco Collaboration Solutions

  • Exam Number/Code : 300-835
  • Exam Name : Automating and Programming Cisco Collaboration Solutions
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
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NEW QUESTION: 1
デバッグフローからのこの出力を調べます。

FortiGateがパケットをドロップしたのはなぜですか?
A. デフォルトの暗黙的なファイアウォールポリシーと一致しました。
B. ネクストホップIPアドレスに到達できません。
C. 明示的に構成されたファイアウォールポリシーをアクションDENYと一致させました。
D. RPFチェックに失敗しました。
Answer: A
Explanation:
https://kb.fortinet.com/kb/documentLink.do?externalID=13900

NEW QUESTION: 2
Which single Cisco IOS ACL entry permits IP addresses from 172.16.80.0 to 172.16.87.255?
A. permit 172.16.80.0 0.0.3.255
B. permit 172.16.80.0 255.255.240.0
C. permit 172.16.80.0 255.255.248.0
D. permit 172.16.80.0 0.0.7.255
E. permit 172.16.80.0 0.0.248.255
F. permit 176.16.80.0 255.255.252.0
Answer: D
Explanation:
www.cisco.com/en/US/products/sw/secursw/ps1018/products_tech_note09186a00800a5b 9a.shtml ACL Summarization Note: Subnet masks can also be represented as a fixed length notation. For example, 192.168.10.0/24 represents 192.168.10.0 255.255.255.0. This list describes how to summarize a range of networks into a single network for ACL optimization. Consider these networks. 192.168.32.0/24 192.168.33.0/24 192.168.34.0/24 192.168.35.0/24 192.168.36.0/24 192.168.37.0/24 192.168.38.0/24 192.168.39.0/24
The first two octets and the last octet are the same for each network. This table is an explanation of how to summarize these into a single network.
The third octet for the previous networks can be written as seen in this table, according to the octet bit position and address value for each bit.
Decimal 128 64 32 16 8 4 2 1 32 0 0 1 0 0 0 0 0 33 0 0 1 0 0 0 0 1 34 0 0 1 0 0 0 1 0 35 0 0 1 0 0 0 1 1 36 0 0 1 0 0 1 0 0 37 0 0 1 0 0 1 0 1 38 0 0 1 0 0 1 1 0 39 0 0 1 0 0 1 1 1 M M M M M D D D
Since the first five bits match, the previous eight networks can be summarized into one network (192.168.32.0/21 or 192.168.32.0 255.255.248.0). All eight possible combinations of the three low-order bits are relevant for the network ranges in question. This command defines an ACL that permits this network. If you subtract 255.255.248.0 (normal mask) from 255.255.255.255, it yields 0.0.7.255. access-list acl_permit permit ip 192.168.32.0 0.0.7.255

NEW QUESTION: 3

A. Option C
B. Option D
C. Option A
D. Option B
E. Option E
Answer: A,C