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Oracle Financials Cloud: General Ledger 2025Implementation Professional
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NEW QUESTION: 1
You have an Azure subscription named Subscription"). Subscription! contains a virtual machine named VM1.
You have a computer named Computer! that runs Windows 10. Computer! is connected to the Internet You add a network interface named interface! to VM1 as shown in the exhibit. (Click the Exhibit tab.)
From Computer1, you attempt to connect to VM1 by using Remote Desktop, but the connection fails.
You need to establish a Remote Desktop connection to VM1.
What should you do first?
A. Delete the DenyAlllnBound inbound port rule.
B. Start VM1.
C. Delete the DenyAIIOutBound outbound port rule.
D. Attach a network interface
Answer: B
Explanation:
Explanation
Note: Rules are processed in priority order, with lower numbers processed before higher numbers, because lower numbers have higher priority. Once traffic matches a rule, processing stops. As a result, any rules that exist with lower priorities (higher numbers) that have the same attributes as rules with higher priorities are not processed.
References: https://docs.microsoft.com/en-us/azure/virtual-network/security-overview
NEW QUESTION: 2
How many bits are available for group IDs in an IPv6 Multicast IP address?
A. 0
B. 1
C. 2
D. 3
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The format of the multicast address defines several scopes and types of addresses using the 4-bit fields Flag and Scope. These fields are located after the FF::/8 prefix. Finally, the low-order 112-bit of the multicast address is the multicast group ID.
http://ptgmedia.pearsoncmg.com/images/chap02_1587050862/elementLinks/02fig15.gif Reference: http://www.ciscopress.com/articles/article.asp?p=31948&seqNum=2
NEW QUESTION: 3
The router address 192.168.1.250 is the default gateway for both the Web Server 2 and Host 1. What is the correct subnet mask for this network?
A. 255.255.255.252
B. 255.255.255.250
C. 255.255.255.128
D. 255.255.255.0
Answer: D
Explanation:
1.Based on the information provided in the exhibit, we know that the IP address of the interface Fa0/0 is 192.168.1.250/24, that is to say the subnet mask is 255.255.255.0??
2.When configuring the correct IP address and not wasting IP address, the network of
192.168.1.0 needs to contain the following three IP addresses of interfaces: R1(fa 0/0) : 192.168.1.250 Host1: 192.168.1.106/24 Web server 2: 192.168.1.10/24 The correct mask is 255.255.255.0.