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Avaya Aura Core Components Implement
- Exam Number/Code : 71201T
- Exam Name : Avaya Aura Core Components Implement
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
Which effect of the passive-interface command on R1 is true?
R1
Interface FastEthernet0/0
description site id:14254489
ip address 172.16.0.1 255.255.0.0
Interface FastEthernet0/1
description site id:14254489
ip address 172.17.0.1 255.255.0.0
router rip
passive-interface FastEthernet0/0
network 172.16.0.0
network 172.17.0.0
version 2
A. It prevents interface Fa0/0 from sending updates.
B. Interface Fa 0/0 operates in RIPv1 mode.
C. It removes the 172.16.0.0 network from all updates on all interfaces on R1.
D. It removes the 172.16.0.0 network from all updates on all interfaces on R1.
Answer: A
NEW QUESTION: 2
Your server has two fully functional NIC's with correct IP configuration. The server is not forwarding traffic between the NIC's. Which command string will set the cards to forward properly?
A. setparam 1 > /proc/sys/net/ipv4/ip_autoconfig
B. vi +/1 /proc/sys/net/unix/max_dgram_qlen
C. set $=1 /proc/sys/net/ipv4/route
D. cat $1 > /proc/sys/net/ethernet
E. echo 1 > /proc/sys/net/ipv4/ip_forward
Answer: E
NEW QUESTION: 3
A. Option D
B. Option E
C. Option B
D. Option A
E. Option C
Answer: E
Explanation:
Switches dynamically learn MAC addresses based on the source MAC addresses that it sees, and since a broadcast is never the source, it will never learn the broadcast address.
NEW QUESTION: 4
A box in the form of a rectangle solid has a square base 5 feet in length and a height of h feet. If the volume of the rectangular solid is 200 cubic feet, which of the following equations may be used to find h?
A. h = 5(200)
B. 25h = 200
C. 5h = 200
D. 5h2 = 200
E. h = 200 ÷ 5
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Use the formula V = lwh. In this case, l = 5, w = 5, and h = h. Therefore, V = 5 × 5 × h =25h and 25h =200.