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NEW QUESTION: 1
You are preparing to capture an image from a Windows 7 reference computer. The reference computer
has a modem installed, and Windows 7 drivers are installed for the modem.
You need to prepare the Windows 7 image so that the image does not contain the modem drivers.
Which two actions should you perform? (Each correct answer presents part of the solution. Choose two.)
A. Use the Sysprep tool with the /audit option.
B. Set the PersistAllDeviceInstalls option to True in an answer file.
C. Include the shellexecute option in the Oobe.xml file.
D. Use the Sysprep tool with the /generalize option.
Answer: A,D

NEW QUESTION: 2
「show ipv6 route」コマンドのサンプルコマンド出力を参照してください。出力に基づいて、デフォルトルートはどのように学習されましたか？

A. Neighbor Discovery Protocol
B. Periodic downloaded static route
C. Per-user static route
D. Connected
Answer: A
Explanation:
Based on the output, there is a default route (::/0) using the FE80::11 link-local address as the next hop. The information is learned via Neighbor Discovery Protocol, as evident from the "ND" letters at the beginning of the routing table entry.
When determining the protocol that derived a router, you need to look at the code presented at the beginning of the routing table entry. A value of "C" indicates a connected route. In this case, the 2001:DB8:C0A8::/64 route is listed as connected, not the default route.
When determining the protocol that derived a router, you need to look at the code presented at the beginning of the routing table entry. A value of "U" indicates a per-user static route. This code was not present in the output.
When determining the protocol that derived a router, you need to look at the code presented at the beginning of the routing table entry. A value of "P" indicates a periodic downloaded static route. This code was not present in the output.

NEW QUESTION: 3
Which two options are commonly used to help calculate the size of an identified risk? (Choose two.)
A. frequency of occurrence
B. number of dependencies
C. complexity of solution
D. number of diagnostic steps
E. level of impact
Answer: A,E

NEW QUESTION: 4
Which three are valid types for switch?
A. integer
B. int
C. String
D. double
E. float
F. Float
Answer: A,B,C
Explanation:
Explanation/Reference:
Explanation:
A switch works with the byte, short, char, and int primitive data types. It also works with enumerated types the String class, and a few special classes that wrap certain primitive types: Character, Byte, Short, and Integer.