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NEW QUESTION: 1

Which address would successfully summarize only the networks seen?
A. 192.168.0.0/24
B. These networks cannot be summarized.
C. 192.168.16.0/21
D. 192.168.8.0/21
E. 192.168.12.0/20
F. 192.168.8.0/20
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number if subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21.
If you make it an binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 00001 000
9 00001 001
10 00001 010
11 00001 011
12 00001 100
13 00001 101
14 00001 110
15 00001 111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0

NEW QUESTION: 2
Which of the following TShark options is used to set capture buffer size in MB?
A. -B
B. -C
C. -F
D. -G
Answer: A

NEW QUESTION: 3
What are pre-requisites for UI adaptions at runtime?
Note: There are 2 correct answers to this question.
A. Getting a UI adaption key.
B. Enabling "Adapt UI" mode.
C. UI built based on SAPUI5 flexibility services.
D. Implementing the adaption code for the UI.
Answer: B,C
Explanation:
Explanation/Reference:
See page 20 and 21 of S4C80 Col17.