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Certified Pega System Architect 24
- Exam Number/Code : PEGACPSA24V1
- Exam Name : Certified Pega System Architect 24
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
- Price:
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NEW QUESTION: 1
HOTSPOT
You are running windows 7 on a portable computer. A custom power plan named "On The Move" is optimized for battery life.
The computer remains running when the portable computer is closed.
You need to change a setting so that when you close the portable computer, it enters sleep mode.
Which setting should you change? (To answer, select the appropriate setting in the work area.)
Answer:
Explanation:
NEW QUESTION: 2
Your customer requires each product to be stored in its own preassigned place in the warehouse. Which putaway strategy meets this requirement? Please choose the correct answer.
A. Fixed storage bin
B. Manual entry
C. Addition to existing stock
D. Empty storage bin
Answer: A
NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
You need to determine the total number of customers who have only loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
B. CustNo IS NULL
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. CustNo = L.CustNo
E. CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
I. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
J. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
K. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
Answer: G
Explanation:
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp
NEW QUESTION: 4
Identify two mandatory attributes for grouping rules. (Choose two.)
A. Sales order (SALES_ORDER)
B. GL date (GL_DATE)
C. Accounting rule (ACCOUNTING_RULE_ID)
D. Currency (CURRENCY_CODE)
Answer: B,D