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Oracle Product Lifecycle Management 2023 Implementation Professional

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  • Exam Name : Oracle Product Lifecycle Management 2023 Implementation Professional
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NEW QUESTION: 1




Answer:
Explanation:

Explanation

http://technet.microsoft.com/es-es/library/jj822938.aspx
They are not talking about Clusters, a single server only, so a standalone server.



NEW QUESTION: 2
Examine the Exhibit.

Which two statements are true about the bloom filter in the execution plan?
A. The bloom filter prevents all rows from table T1 that do not join T2 from being needlessly distributed.
B. The bloom filter prevents all rows from table T2 that do not join table T1 from being needlessly distributed.
C. The bloom filter is created in parallel by the set of parallel execution processes that scanned table T2.
D. The bloom filter is created in parallel by the set of parallel execution processes that later perform join.
E. The bloom filter is created in parallel by the set of parallel execution processes that scanned table T1.
F. The bloom filter prevents some rows from table T2 that do not join table T1 from being needlessly distributed.
Answer: B,E
Explanation:
* PX JOIN FILTER CREATE The bloom filter is created in line 4.
*PX JOIN FILTER USE The bloom filter is used in line 11.
Note:
*You can identify a bloom pruning in a plan when you see :BF0000 in the Pstart and Pstop columns of the execution plan and PART JOIN FILTER CREATE in the operations column.
*A Bloom filter is a probabilistic algorithm for doing existence tests in less memory than a full list of keys would require. In other words, a Bloom filter is a method for representing a set of n elements (also called keys) to support membership queries.
*The Oracle database makes use of Bloom filters in the following 4 situations:
-
To reduce data communication between slave processes in parallel joins: mostly in RAC
-
To implement join-filter pruning: in partition pruning, the optimizer analyzes FROM and WHERE clauses in SQL statements to eliminate unneeded partitions when building the partition access list
-
To support result caches: when you run a query, Oracle will first see if the results of that query have already been computed and cached by some session or user, and if so, it will retrieve the answer from the server result cache instead of gathering all of the database blocks
-
To filter members in different cells in Exadata: Exadata performs joins between large tables and small lookup tables, a very common scenario for data warehouses with star schemas. This is implemented using Bloom filters as to determine whether a row is a member of the desired result set.

NEW QUESTION: 3
View the Exhibits and examine PRODUCTS and SALES tables.

You issue the following query to display produce name and the number of times the product has been sold:
SQL>SLECT p. PROD_name, i . item _cnt
FROM (SELECT prod_id =, count (*) item_cnt
FROMm sales
GROUP BY prod_id) I RIGHT OUTER JION products p
On i. prod _id =.prod_id;
What happens when the above statement is executed?
A. The statement produces an error ITEM_CNT cannot be displayed in the outer query.
B. The statement produce an error because a subquery in the FROM clause and outer-jions cannot be together.
C. the statement executes successfully and produces the required output.
D. The statement produces an error because the GROUP By clause cannot be usesd in a subquery in the FROM clause.
Answer: C

NEW QUESTION: 4
Refer to the exhibit. Which two statements are true about the loopback address that is configured on RouterB? (Choose two.)

A. It provides stability for the OSPF process on RouterB.
B. It indicates that RouterB should be elected the DR for the LAN.
C. It specifies that the router ID for RouterB should be 10.0.0.1.
D. It ensures that data will be forwarded by RouterB.
E. It decreases the metric for routes that are advertised from RouterB.
Answer: A,C
Explanation:
A loopback interface never comes down even if the link is broken so it provides stability for the OSPF process (for example we use that loopback interface as the router-id) - The router-ID is chosen in the order below:
+ The highest IP address assigned to a loopback (logical) interface. + If a loopback interface is not defined, the highest IP address of all active router's physical interfaces will be chosen.
-> The loopback interface will be chosen as the router ID of RouterB -