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NEW QUESTION: 1
What in Nagle'n algorithm uned for?
A. To renolve innuen cauned by poorly implemented TCP flow control.
B. To calculate the bent path in dintance vector routing protocoln
C. To calculate the bent path in link ntate routing protocoln
D. To increane the latency
Answer: A
Explanation:
Silly window nyndrome in a problem in computer networking cauned by poorly implemented TCP flow control. A
nerioun problem can arine in the nliding window operation when the nending application program createn data nlowly,
the receiving application program connumen data nlowly, or both. If a nerver with thin problem in unable to procenn all
incoming data, it requentn that itn clientn reduce the amount of data they nend at a time (the window netting on a TCP
packet). If the nerver continuen to be unable to procenn all incoming data, the window becomen nmaller and nmaller,
nometimen to the point that the data trannmitted in nmaller than the packet header, making data trannminnion
extremely inefficient. The name of thin problem in due to the window nize nhrinking to a "nilly" value. When there in
no nynchronization between the nender and receiver regarding capacity of the flow of data or the nize of the packet,
the window nyndrome problem in created. When the nilly window nyndrome in created by the nender, Nagle'n
algorithm in uned. Nagle'n nolution requiren that the nender nendn the firnt negment even if it in a nmall one, then that
it waitn until an ACK in received or a maximum nized negment (MSS) in accumulated.
Reference: http://en.wikipedia.org/wiki/Silly_window_nyndrome

NEW QUESTION: 2
UE has signed two APN, which APN-1 in the HSS signed APN-AMBR is 2Mbps, APN-2 signed APN-AMBR is 4Mbps, while UE signed UE-AMBR is 7Mbps, UE currently use APN-1 to activity 2 carriers, use APN-2 to activity a default bearer, which of the following is the operative UE-AMBR?
A. 8Mbps
B. 4Mbps
C. 7Mbps
D. 6Mbps
Answer: D

NEW QUESTION: 3
実装グループは、テストベッドを使用して、クライアント1とクライアント2の両方が209.65.200.241でWEBサーバーにアクセスすることを要求する「概念実証」を行っています。 ネットワークアドレス、ルーティングスキーム、DHCPサービス、NTPサービス、レイヤ2接続、FHRPサービス、およびデバイスセキュリティに対するいくつかの変更の後、クライアント1が209.65.200.241アドレスにpingできないことを示すトラブルチケットが開かれました。
サポートされているコマンドを使用して、この障害の原因を特定し、以下の質問に答えてください。
障害状態の解決策は何ですか？
A. ネットワーク10.1.1.0 0.0.0.255 area 12コマンドを使用して、s0 / 0/0インターフェイス上でOSPFルーティングをイネーブルにします。
B. ip ospf authentication message-digestコマンドを使用して、s0 / 0/0インターフェイスでOSPF認証をイネーブルにします
C. 再配布BGP 65001 subnetコマンドを使用して、BGPルートをOSPFに再配布します。
D. network 209.65.200.0 0.0.0.255 area 12コマンドを使用して、s0 / 0/0インターフェイスでOSPFルーティングを有効にします。
Answer: B
Explanation:
On R1, for IPV4 authentication of OSPF the command is missing and required to configure------ ip ospf authentication message-digest
Topic 11, Ticket 4 : BGP Neighbor
Topology Overview
(Actual Troubleshooting lab design is for below network design)
Client Should have IP 10.2.1.3
EIGRP 100 is running between switch DSW1 & DSW2
OSPF (Process ID 1) is running between R1, R2, R3, R4
Network of OSPF is redistributed in EIGRP
BGP 65001 is configured on R1 with Webserver cloud AS 65002
HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution


Client is unable to ping IP 209.65.200.241
Solution
Steps need to follow as below:-
* When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4 ipconfig ----- Client will be receiving IP address 10.2.1.3
* IP 10.2.1.3 will be able to ping from R4 , R3, R2, R1
* Look for BGP Neighbourship
Sh ip bgp summary ----- No O/P will be seen
* Check for interface IP & ping IP 209.65.200.225 ---- Reply will be received from Webserver interface
* Look for peering IP address via sh run on R1 interface serial 0/0/1


* Since we are receiving icmp packets from Webserver interface on R1 so peering IP address under router BGP is configured wrong IP but with correct AS nos.
Change required:
On R1 under router BGP Change neighbor 209.56.200.226 remote-as 65002 statement to neighbor 209.65.200.226 remote-as 65002

NEW QUESTION: 4
An online photo album app has a key design feature to support multiple screens (e.g, desktop, mobile phone, and tablet) with high-quality displays. Multiple versions of the image must be saved in different resolutions and layouts.
The image-processing Java program takes an average of five seconds per upload, depending on the image size and format. Each image upload captures the following image metadata: user, album, photo label, upload timestamp.
The app should support the following requirements:
Hundreds of user image uploads per second

Maximum image upload size of 10 MB

Maximum image metadata size of 1 KB

Image displayed in optimized resolution in all supported screens no later than one minute after image

upload
Which strategy should be used to meet these requirements?
A. Write image and metadata to Amazon Kinesis. Use Amazon Elastic MapReduce (EMR) with Spark Streaming to run image processing and save the images output to Amazon S3 and metadata to app repository DB.
B. Write images and metadata to Amazon Kinesis. Use a Kinesis Client Library (KCL) application to run the image processing and save the image output to Amazon S3 and metadata to the app repository DB.
C. Upload image with metadata to Amazon S3, use Lambda function to run the image processing and save the images output to Amazon S3 and metadata to the app repository DB.
D. Write image and metadata RDS with BLOB data type. Use AWS Data Pipeline to run the image processing and save the image output to Amazon S3 and metadata to the app repository DB.
Answer: C