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NEW QUESTION: 1
Which option describes the purpose of traffic policing?
A. It prioritizes routing protocol traffic.
B. It queues and then transmits traffic that exceeds the CIR.
C. It remarks traffic that is below the CIR
D. It drops traffic that exceeds the CIR.
Answer: D
Explanation:
Traffic policing allows you to control the maximum rate of traffic transmitted or received on an interface. Traffic
policing is often configured on interfaces at the edge of a network to limit traffic into or out of the network. In most
Traffic Policing configurations, traffic that falls within the rate parameters is transmitted, whereas traffic that exceeds
the parameters is dropped or transmitted with a different priority.

NEW QUESTION: 2
A customer has decided they will NOT use the standard weekly hours field on the Foundation Object Legal Entity in their implementation.
What is the SAP SuccessFactors recommendation to configure this field?
Please choose the correct answer.
Response:
A. Delete the association to the field
B. Delete the field from the list of fields
C. Set the visibility of the field to none
D. Set the status of the field to inactive
Answer: C

NEW QUESTION: 3
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 8 kHz x 4-bit code words
B. 2 x 4-bit code words x 8 kHz
C. 8 kHz x 8-bit code words
D. 2 x 4 kHz x 8-bit code words
Answer: D
Explanation:
Explanation/Reference:
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per second = 64 Kbps) Reference: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original perfectly from the sampled version."

NEW QUESTION: 4
Drag and Drop Question
You have an Azure subscription that contains an Azure Service Bus named Bus1.
Your company plans to deploy two Azure web apps named App1 and App2. The web apps will create messages that have the following requirements:
- Each message created by App1 must be consumed by only a single
consumer
- Each message created by App2 will be consumed by multiple consumers.
Which resource should you create for each web app? To answer, drag the appropriate resources to the correct web apps. Each resource may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to vie NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation:
App1: A service Bus queue
In Queues each message is processed by a single consumer.
App2: A Service Bus topic
In contrast to queues, in which each message is processed by a single consumer, topics and subscriptions provide a one many form of communication, in a publish/subscribe pattern.
References:
https://www.codit.eu/blog/exploring-azure-event-grid-are-service-bus-topic-dead/