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  • Exam Number/Code : API-580
  • Exam Name : Risk Based Inspection Professional
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
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NEW QUESTION: 1
あなたには、以下のコード(行番号は参考のために含まれるだけです)があります:

あなたは、Connectionの新しい例がCreate方法を呼ぶことによって他のクラスだけによってつくられることができることを確実とする必要があります。解決策は、クラスが接続を継承できるようにする必要があります。

A. Option C
B. Option B
C. Option D
D. Option A
Answer: B
Explanation:
Explanation
The following list provides the main features of a static class:
* Contains only static members.
* Cannot be instantiated.
* Is sealed.
* Cannot contain Instance Constructors.
Creating a static class is therefore basically the same as creating a class that contains only static members and a private constructor. A private constructor prevents the class from being instantiated.
Incorrect:
Not A: An abstract method is a method that is declared without an implementation.
Not C: Private methods can be called from derived classes.
Reference: Static Classes and Static Class Members (C# Programming Guide)
https://msdn.microsoft.com/en-us/library/79b3xss3.aspx

NEW QUESTION: 2
On the Interceptor appliance what is the size of the datastore?
A. 600 MB
B. 4.8 TB
C. 1.2 TB
D. 0 MB
E. 3.6 TB
Answer: D

NEW QUESTION: 3
Which two IPv6 address pairs can be assigned on a point-to-point link with a /125 mask? (Choose two.)
A. 2001:DB8::10 and 2001:DB8::17
B. 2001:DB8::9 and 2001:DB8::10
C. 2001:DB8::1 and 2001:DB8::2
D. 2001:DB8::1 and 2001:DB8::18
Answer: A,C
Explanation:
2001:DB8::x/125 = 2001:0DB8:0000:0000:0000:0000:0000:00xx
1- The 0's disapear because the 3 zero ommiting rules: Leading zeros can be omitted Groups of four zeros can be abbreviated to a zero Multiple contiguous groups (2-byte groups) can be abbreviated to double colon (::) but only once. 2- IPv6 is made by 128bits, therefore 128-125 = 3 This means that the last 3 bits represent the hosts, just like in IPv4 3- IPv6 is represented in Hex numbers: Ex: 2001 = 00100001 4- Then you can determine the answer just like in IPv4 (or at least in a very similar way) 2001:DB8::1 and 2001:DB8::2 belong to the /125 mask because of the 3 last bits 2001:DB8::9 and 2001:DB8::10 are obviously not in the same /125 subnet (remember 10 in hex is much different thatn 10 in decimal) 2001:DB8::10 and 2001:DB8::17 fall into the /125 subnet 2001:DB8::1 and 2001:DB8::18 it goes beyond the /125 subnet 5- In case you didn't understand why: 2001:DB8::1 - 2001:DB8::9 = First Subnet's Host 2001:DB8::10 - 2001:DB8::18 = Second Subnet's Hosts