Thus Choice 'c' is the correct answer and the other choices are wrong.
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- Exam Number/Code : 2). This implies the combined VaR of a portfolio with these two securities will be less than the sum of VaRs of the two individual securities.
Thus Choice 'c' is the correct answer and the other choices are wrong.
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NEW QUESTION: 1
For each intermediate key, each reducer task can emit:
A. One final key-value pair per key; no restrictions on the type.
B. As many final key-value pairs as desired, but they must have the same type as the intermediate key-value pairs.
C. As many final key-value pairs as desired. There are no restrictions on the types of those key-value pairs (i.e., they can be heterogeneous).
D. One final key-value pair per value associated with the key; no restrictions on the type.
E. As many final key-value pairs as desired, as long as all the keys have the same type and all the values have the same type.
Answer: E
Explanation:
Reference: Hadoop Map-Reduce Tutorial; Yahoo! Hadoop Tutorial, Module 4: MapReduce
NEW QUESTION: 2
Which three statements about L2TPv3 are true? (Choose three)
A. L2TPv3 feature does not support Frame Relay extended addressing.
B. To use DCE or a Network-to-Network Interface on a Frame Relay port, you must configure the frame-relayswitching command.
C. L2TPv3 sessions do not support Frame Relay LMI interworking.
D. Multipoint DLCI is not supported.
E. L2TPv3 Frame Relay support includes only 32-bit DLCI addressing.
Answer: A,B,D
Explanation:
Frame Relay-Specific Restrictions
*Frame Relay per-DLCI forwarding and port-to-port trunking are mutually exclusive.
L2TPv3 does not support the use of both on the same interface at the same time.
*The xconnect command is not supported on Frame Relay interfaces directly. For Frame Relay, the Xconnect is applied under the connect command specifying the DLCI to be used.
*Changing the encapsulation type on any interface removes any existing xconnect command applied to that interface.
*To use DCE or a Network-to-Network Interface (NNI) on a Frame Relay port, you must configure the framerelay switching command.
*The configuration of an L2TPv3 session on a Multilink Frame Relay (MLFR) bundle interface is supported only on Cisco 12000 series Two-Port Channelized OC-3/STM-1 (DS1/E1) and Six-Port Channelized T3 (T1) line cards. (For more information, see Binding L2TPv3 Sessions to Multilink Frame Relay Interfaces.) *Frame Relay policing is nondistributed on the Cisco 7500 series. By configuring Frame Relay policing, you cause traffic on the affected PVCs to be sent to the RSP for processing.
*Frame Relay support is for 10-bit DLCI addresses. Frame Relay Extended Addressing is not supported.
*Multipoint DLCI is not supported.
*The keepalive will automatically be disabled on interfaces that have an Xconnect applied to them, except for Frame Relay encapsulation, which is a requirement for LMI.
*Static L2TPv3 sessions will not support Frame Relay LMI interworking.
NEW QUESTION: 3
If A and B be two uncorrelated securities, VaR(A) and VaR(B) be their values-at-risk, then which of the following is true for a portfolio that includes A and B in any proportion. Assume the prices of A and B are log-normally distributed.
A. The combined VaR cannot be predicted till the correlation is known
B. VaR(A+B) > VaR(A) + VaR(B)
C. VaR(A+B) < VaR(A) + VaR(B)
D. VaR(A+B) = VaR(A) + VaR(B)
Answer: C
Explanation:
Explanation
First of all, if prices are lognormally distributed, that implies the returns (which are equal to the log of prices) are normally distributed. To say that prices are lognormally distributed is just another way of saying that returns are normally distributed.
Since the correlation between the two securities is zero, this means their variances can be added. But standard deviations, or volatilities cannot be added (they will be the square root of sum of variances). VaR is nothing but a multiple of standard deviation, and therefore it is not additive if correlations are anything other than 1 (ie perfect positive, which would imply we are dealing with the same asset). Therefore VaR(A+B)=SQRT(VaR(A)
