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NEW QUESTION: 1
Which file must be configured to allow remote scanning of network volumes through a Windows proxy FSV host?
A. nas.properties
B. FileSRMProvider.properties
C. UncShares.xml
D. cim.extension.parameters
Answer: C

NEW QUESTION: 2
조직은 구획화를 위해 단일 응용 프로그램의 여러 구성 요소를 만들었습니다. 현재 모든 구성 요소는 단일 EC2 인스턴스에서 호스팅됩니다. 보안상의 이유로 조직에서는 이미 VPC를 사용하고 있지만 별도의 모듈에 대해 두 개의 별도 SSL을 구현하려고 합니다.
조직은 어떻게 단일 인스턴스로 이를 수행 할 수 있습니까?
A. 별도의 서브넷에서 각각 두 개의 인스턴스를 시작하고 단일 IP에 대해 VPC 피어링을 허용해야 합니다.
B. 여러 서브넷이 연결될 VPC 인스턴스를 만들고 각각에 별도의 IP 주소가 있습니다.
C. ACL과 보안 그룹이 모두 연결된 VPC 인스턴스를 만들고 각 IP 주소에 대해 별도의 규칙을 지정합니다.
D. 여러 개의 탄성 IP 주소가있는 다중 네트워크 인터페이스가있는 VPC 인스턴스를 만듭니다.
Answer: D
Explanation:
설명
가상 사설망 (VPC)은 사용자의 AWS 계정 전용 가상 네트워크입니다. 이를 통해 사용자는 AWS 리소스를 사용자가 정의한 가상 네트워크로 시작할 수 있습니다. With VPC the user can specify multiple private IP addresses for his instances.
The number of network interfaces and private IP addresses that a user can specify for an instance depends on the instance type. With each network interface the organization can assign an EIP. This scenario helps when the user wants to host multiple websites on a single EC2 instance by using multiple SSL certificates on a single server and associating each certificate with a specific EIP address. It also helps in scenarios for operating network appliances, such as firewalls or load balancers that have multiple private IP addresses for each network interface.
http://docs.aws.amazon.com/AWSEC2/latest/UserGuide/MultipleIP.html

NEW QUESTION: 3
Sie haben ein Microsoft 365 Enterprise-Abonnement.
Sie erstellen eine Kennwortrichtlinie, wie in der folgenden Abbildung gezeigt.

Verwenden Sie die Dropdown-Menüs, um die Antwortauswahl auszuwählen, die die einzelnen Anweisungen anhand der in der Grafik angezeigten Informationen vervollständigt.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Explanation

By default, smart lockout locks the account from sign-in attempts for one minute after 10 failed attempts. In this question, the lockout threshold if 5 failed attempts. The account locks again after each subsequent failed sign-in attempt, for one minute at first and longer in subsequent attempts.
Password evaluation goes through several steps including normalization and Substring matching which is used on the normalized password to check for the user's first and last name as well as the tenant name.
The next step is to identify all instances of banned passwords in the user's normalized new password. Then:
* Each banned password that is found in a user's password is given one point.
* Each remaining unique character is given one point.
* A password must be at least five (5) points for it to be accepted.
Conto$01Pa$$word contains two banned passwords and no remaining unique characters so is given a score of
2 points. This is less than the required 5 points so will be rejected.
Pa$$w0rd contains a banned password and no remaining unique characters so is given a score of 1 point. This is less than the required 5 points so will be rejected.
AzureAD!!111 contains a banned password (AzureAD!!) and has three remaining characters. However, the remaining characters are all the same (they're all 1s) so that is only one unique character. So that password will be given a score of 2. One for the banned password and 1 for the unique character. This is less than the required 5 points so will be rejected.
Password11 does not contain a banned password. Password11 contains 10 characters. However, there are two
's' and two '1' so there are 8 unique characters. Therefore, the password will be given a score of 8 points. This is more than the required 5 points so the password will be accepted.
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/authentication/concept-password-ban-bad
https://docs.microsoft.com/en-us/azure/active-directory/authentication/howto-password-smart-lockout

NEW QUESTION: 4
The following SAS program is submitted:

What is the value of the macro variable Newval when the %PUT statement executes?
A. 0.555
B. 2.2
C. 0
D. 1
Answer: D
Explanation:
Explanation/Reference:
Explanation:
%PUT statement shows that %EVAL discards the fractional part when it performs division on integers that would result in a fraction.