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Salesforce Certified MuleSoft Integration Architect I
- Exam Number/Code : MuleSoft-Integration-Architect-I
- Exam Name : Salesforce Certified MuleSoft Integration Architect I
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
注:この質問は、同じシナリオを提示する一連の質問の一部です。
シリーズの各質問には、上記の目標を達成できる独自の解決策が含まれています。 いくつかの質問セットには1つ以上の正しい解決策があるかもしれないが、他の質問セットには正しい解決策がないかもしれない。
このセクションの質問に答えると、それに戻ることはできません。 その結果、これらの質問はレビュー画面に表示されません。
Sales.CustomersおよびSales.Ordersという名前の2つのテーブルを含むDB1という名前のデータベースがあります。
Sales.Customersには、SalesOrdersのCustomerIDという列との外部キー関係があります。
すべての顧客を返すクエリを推奨する必要があります。 このクエリは、各顧客が2016年に配置した注文の数も返す必要があります。
解決策:次のクエリを推奨します。
Does this meet the goal?
A. No
B. Yes
Answer: A
NEW QUESTION: 2
PP-
Which business processed are included in the Line of Business area of Accelerated Plan to Product? Note: There are 2 correct answers to this question
A. Maintenance Management
B. Inventory Management
C. Project Management
D. Operational Procurement
Answer: A,B
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:
Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: A
Explanation:
Explanation
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1
NEW QUESTION: 4
Northern Trail Outfitters (NTO) wants to launch an email campaign for its new winter gear. The NTO sales representative will review the response to the campaign and determine who the decision makers are prior to the beginning the sales process with each respondent. What set of steps should the consultant recommend for NTO?
A. Create both account and contact records, then associate the contacts to the campaign
B. Create a campaign, associate the leads to the campaign, and qualify the respondents.
C. Create leads, convert them to opportunities, and qualify the respondents on the opportunities
D. Create a campaign, qualify the respondents, and create accounts and contacts
Answer: B