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NEW QUESTION: 1
Which of the following is MOST important for an information security manager to ensure when evaluating change requests?
A. Residual risk is within risk tolerance.
B. Contingency plans have been created.
C. Requests add value to the business.
D. Requests are approved by process owners.
Answer: A

NEW QUESTION: 2
The Operations team at Fire Extinguishers Ltd has recently launched Slack and wants to better collaborate when internal alerting systems notify them of a failure. In the past, it was difficult to identify where the alert was coming from and who was responding. Sometimes, the team even missed the alerts.
The Operations team and the Security team both have alerting set up with popular software tools, and the alerts get sent to multiple, unrelated teams.
What should Fire Extinguishers Ltd do to centralize their alerting identification and response?
A. Install apps from the Slack App Directory for the tools they use, and have the apps post alerts in a
#alerts- all channel for the relevant teams to monitor.
B. Send an announcement to the company reminding them to be more responsive when receiving alerts.
C. Set up Slackbot custom responses to trigger when the word "alert" or "failure" is used in Slack.
D. Build custom apps for all the popular tools that send the alerts to one channel.
Answer: D

NEW QUESTION: 3
Given the fragment:
String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
// insert code fragment here
Which code fragment when inserted at line '// insert code fragment here', enables thecode to successfully change arra elements to uppercase?
A. for (int i = 0; i < 3; i++) {
for (int j=0; j< 4; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
B. toUpperCase();
}
}
C. String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
for (int i = 0; i < arra.length; i++) {
for (int j=0; j < arra[i].length; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
D. for (int i:arra.length) {
for (String x:arra) {
arra[i].toUpperCase();
}
}
E. for (String a[]:arra[][]) {
for (String x:a[]) {
Answer: E
Explanation:
Incorrect:
not A: arra.length is 3, but the subarrays have 2, 3 and 4 elements. Index will be out of
bound.
not B: The subarrys are of different lengths. Indexwill be out of bound.
not D: Compile error.

NEW QUESTION: 4

A. Option D
B. Option A
C. Option B
D. Option C
Answer: A,D
Explanation: