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Professional Chrome Enterprise Administrator Certification Exam

  • Exam Number/Code : Chrome-Enterprise-Administrator
  • Exam Name : Professional Chrome Enterprise Administrator Certification Exam
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
You administer a Microsoft SQL Server 2012 database that includes a table named Products. The Products table has columns named Productld, ProductName, and CreatedDateTime. The table contains a unique constraint on the combination of ProductName and CreatedDateTime. You need to modify the Products table to meet the following requirements:
Remove all duplicates of the Products table based on the ProductName column.
Retain only the newest Products row. Which Transact-SQL query should you use?
A. WITH CTEDupRecords AS (
SELECT MIN(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
B. WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
C. WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
p.ProductName = cte.ProductName
AND p.CreatedDateTime > cte.CreatedDateTime
D. WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
)
DELETE p
FROM Products p
JOIN CTEDupRecords cte ON
cte.ProductName = p.ProductName
AND cte.CreatedDateTime > p.CreatedDateTime
Answer: D
Explanation:
--Burgos - NO I changed answer to B (previous was A) because is imposseble to delete products with CreateDateTime greater than MAX(CreateDateTime). In fact will exists ONE AND ONLY ONE record with CreateDateTime EQUAL TO MAX(CreateDateTime), all records with same ProductName have a lower than MAX (CreateDateTime). I tested both choices anda ONLY B is correct. Use the code below to test (note that SELECT will catch only rows to be deleted:
--Exam A Q028
CREATE TABLE Products (
Productld int identity (1, 1) not null,
ProductName varchar (10) not null,
CreatedDateTime datetime not null,
constraint PK_Products PRIMARY KEY CLUSTERED (Productld)
)
GO
ALTER TABLE Products ADD CONSTRAINT UQ_Products UNIQUE (ProductName,
CreatedDateTime)
GO
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 1', '201010-10')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 1', '201111-11')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 1', '201212-12')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 2', '201010-10')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 2', '201212-12')
INSERT INTO Products (ProductName, CreatedDateTime) VALUES ('Product 3', '201010-10')
GO
WITH CTEDupRecords AS
(
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
) select p.* FROM Products p JOIN CTEDupRecords cte ON p.ProductName = cte.ProductName AND p.CreatedDateTime > cte.CreatedDateTime GO WITH CTEDupRecords AS (
SELECT MAX(CreatedDateTime) AS CreatedDateTime, ProductName
FROM Products
GROUP BY ProductName
HAVING COUNT(*) > 1
) select p.* FROM Products p JOIN CTEDupRecords cte ON cte.ProductName = p.ProductName AND cte.CreatedDateTime > p.CreatedDateTime GO
PS: In v.2012-10-17.by.Alex.142q this exercise appears with choice A using "<" instead of ">", so, in Alex we have two correct answers (A and B). --\Burgos
Verified answer as correct.

NEW QUESTION: 2
Testlet: City Power & Light
You need to recommend a management solution for Server1 that meets the company's security requirements.
What should you include in the recommendation?
Plight1 (exhibit):

Plight2 (exhibit):

A. Access-based enumeration (ABE)
B. Authorization Manager
C. Hyper-V Manager
D. AuthenticationMechanismAssurance
Answer: B
Explanation:
http://technet.microsoft.com/en-us/library/cc732290%28WS.10%29.aspx
What doesAuthorization Manager do?
Authorization Manager is a role-based security architecture for Windows that can be used in any application that needs role-based authorization, including ASP.NET Web applications, ASP.NET Web services, and client/server systems based on .NET Remoting. The role-based management model enables you to assign users to roles and gives you a central place to record permissions assigned to each role. This model is often called role-based access control.

NEW QUESTION: 3
アンは傍受している代理人を通してマーケティングウェブサイトの頑健性をテストしています。彼女は次のHTTPリクエストを傍受しました:
POST /login.aspx HTTP / 1.1
ホスト:comptia.org
コンテンツタイプ:text / html
txtUsername = ann&txtPassword = ann&alreadyLoggedIn = false&submit = true
Webサイトが単純な認証バイパスの影響を受けやすいかどうかをテストするために、Annはどれを実行すべきですか。
A. 投稿データをすべて削除し、/login.aspxへの要求をPOSTからGETに変更します。
B. txtUsernameとtxtPasswordの投稿データを削除し、送信をtrueからfalseに切り替えます。
C. txtPassword投稿データを削除し、alreadyLoggedInをfalseからtrueに変更します。
D. パスワードクラッカーを使ってすべてのユーザー名とパスワードをブルートフォースしようとした
Answer: C
Explanation:
Explanation
The text "txtUsername=ann&txtPassword=ann" is an attempted login using a username of 'ann' and also a password of 'ann'.
The text "alreadyLoggedIn=false" is saying that Ann is not already logged in.
To test whether we can bypass the authentication, we can attempt the login without the password and we can see if we can bypass the 'alreadyloggedin' check by changing alreadyLoggedIn from false to true. If we are able to log in, then we have bypassed the authentication check.