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NEW QUESTION: 1
An administrator notices that nothing is being archived during scheduled archiving. However, users are able to archive manually from Outlook.
What should the administrator check first to ensure items are archived during scheduled archiving?
A. verify the Mailbox Archiving task is running
B. verify the Provisioning task is running
C. verify "Initially Suspend Archiving" is unchecked in the provisioning group
D. verify the Mailbox Archiving task has Report mode unchecked
Answer: D

NEW QUESTION: 2
Relativ gesehen sind Firewalls, die auf Anwendungsebene des Siebenschicht-OSI-Modells betrieben werden:
A. fast immer weniger sicher.
B. fast immer weniger effizient.
C. fast immer weniger effektiv.
D. Die Einrichtung ist fast immer kostengünstiger.
E. Keine der Auswahlmöglichkeiten.
Answer: B
Explanation:
Erläuterung:
Erste Versuche zur Herstellung von Firewalls wurden auf Anwendungsebene des Sieben-Schichten-OSI durchgeführt
Modell, aber dies erfordert zu viel CPU-Rechenleistung.
Paketfilter arbeiten auf der Netzwerkebene und arbeiten effizienter, weil sie nur die Netzwerkebene betrachten
der Header-Teil eines Pakets.

NEW QUESTION: 3
コードの断片を考えると：
class Caller implements Callable<String> {
String str;
public Caller (String s) {this.str=s;}
public String call()throws Exception { return str.concat ("Caller");}
}
class Runner implements Runnable {
String str;
public Runner (String s) {this.str=s;}
public void run () { System.out.println (str.concat ("Runner"));}
}
and
public static void main (String[] args) InterruptedException,
ExecutionException {
ExecutorService es = Executors.newFixedThreadPool(2);
Future f1 = es.submit (new Caller ("Call"));
Future f2 = es.submit (new Runner ("Run"));
String str1 = (String) f1.get();
String str2 = (String) f2.get();//line n1
System.out.println(str1+ ":" + str2);
}
結果は何ですか？
A. The program terminates after printing:
Run Runner
Call Caller : Run
B. A compilation error occurs at line n1.
C. An Execution is thrown at run time.
D. The program prints:
Run Runner
Call Caller : null
And the program does not terminate.
Answer: D