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IBM Blueworks Live and Business Automation Workflow Business Analyst v18

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  • Exam Name : IBM Blueworks Live and Business Automation Workflow Business Analyst v18
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NEW QUESTION: 1



A. Option B
B. Option C
C. Option A
D. Option D
Answer: D
Explanation:
javac Test.java
will compile the program.
As for command line:
java ea Test
First the code will produce the output:
Standard Edition
See Note below.
The ea option will enable assertions. This will make the following line in the switch statement to be
run:
default: assert false;
This will throw an assertion error. This error will be caught. An the class of the assertion error
(class java.lang.AssertionError) will be printed by the following line:
System.out.println(e.getClass());
Note:The java tool launches a Java application. It does this by starting a Java runtime
environment, loading a specified class, and invoking that class's main method. The method
declaration must look like the following:
public static void main(String args[])
Paramater ea:
-enableassertions[:<package name>"..." | :<class name> ] -ea[:<package name>"..." | :<class
name> ]
Enable assertions. Assertions are disabled by default. With no arguments, enableassertions or -ea enables assertions.
Note 2:
An assertion is a statement in the JavaTM programming language that enables you to test your assumptions about your program. Each assertion contains a boolean expression that you believe will be true when the assertion
executes. If it is not true, the system will throw an error.
public class AssertionError extends Error
Thrown to indicate that an assertion has failed.
Note 3:
The javac command compiles Java source code into Java bytecodes. You then use the Java
interpreter - the
java command - to interprete the Java bytecodes.
Reference:java - the Java application launcher
Reference:java.langClass AssertionError

NEW QUESTION: 2
You have created two transactions with a 30-day payment term. The first transaction is on January 29,
2015 and the second transaction is on January 31, 2015. The invoice date is the same as the system date.
Both transactions are assigned an unsigned receipt method that has the lead days set to 60, number of bills receivable rule set to one per customer, and the bills receivable maturity date rule set to latest.
Which statement is true when the create bills receivable batch is processed for a customer on January 31,
2015?
A. A Bills Receivable is created with the issue date as January 31, 2015 and the maturity date as February 28, 2015.
B. A Bills Receivable is created with the issue date as January 31, 2015 and the maturity date as March 2,
2015.
C. Two Bills Receivable transactions are created with maturity dates as March 30, 2015 and April 1, 2015.
D. A Bills Receivable is created with the issue date as January 31, 2015 and the maturity date as March
30, 2015.
E. Two Bills Receivable transactions are created with the issue date and accounting date as January 29,
2015 and January 31, 2015, respectively.
F. Two Bills Receivable transactions are created with the issue dates as January 29, 2015 and January
31, 2015.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Oracle Receivables treats a bill receivable as a separate transaction.
Issue Date is the date that the bill was first issued.
Maturity Date is the date when full payment is due on the bill.
Incorrect Answers:
A, C, F: Oracle Receivables treats a bill receivable as a separate transaction.
References: https://docs.oracle.com/cd/E18727_01/doc.121/e13522/T355475T355479.htm

NEW QUESTION: 3
What happens when you attempt to compile and run the following code? Choose all that apply.
#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <algorithm>
#include <iomanip>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<setw(3)<<hex<<val; } };
int main () {
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f("test.out", ios::trunc|ios::out);
list<B> l(t, t+10);
for_each(l.begin(), l.end(), Out<B>(f));
f.close();
f.open("test.out");
for( ; f.good() ; ) {
int i;
f>>i;
cout<<i<<" ";
}
f.close();
return 0;
}
A. file test.out will be truncated
B. file test.out will be opened for reading
C. no file will be created nor opened
D. file test.out will be opened writing
E. program will display sequence 1 2 3 4 5 6 7 8 9 10
Answer: A,B,D,E