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HCIA-Computing V3.0

  • Exam Number/Code : H13-211_V3.0
  • Exam Name : HCIA-Computing V3.0
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
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NEW QUESTION: 1

A. Option K
B. Option D
C. Option E
D. Option B
E. Option G
F. Option C
G. Option L
H. Option F
I. Option A
J. Option H
K. Option J
L. Option I
Answer: E
Explanation:
Host Priorities Each cluster host is assigned a unique host priority in the range of 1 to 32, where lower numbers denote higher priorities. The host with the highest host priority (lowest numeric value) is called the default host. It handles all client traffic for the virtual IP addresses that is not specifically intended to be load-balanced. This ensures that server applications not configured for load balancing only receive client traffic on a single host. If the default host fails, the host with the next highest priority takes over as default host.
Reference: Network Load Balancing Technical Overview
http://technet.microsoft.com/en-us/library/bb742455.aspx

NEW QUESTION: 2
Where would an administrator set the option to push out new client preference parameters?
A. Global settings policy, Custom Client Preferences tab
B. Custom policy settings document, Custom Settings > Notes.ini tab
C. Server Configuration document, Client Preferences tab
D. Desktop policy settings document, Custom Settings > Notes.ini tab
Answer: D

NEW QUESTION: 3


Answer:
Explanation:

Explanation


NEW QUESTION: 4
var numbers = List.of(0,1,2,3,4,5,6,7,8,9);
You want to calculate the average of numbers. Which two codes will accomplish this? (Choose two.)
A. double avg = numbers.parallelStream().mapToInt (m > m).average().getAsDouble ();
B. double avg = numbers.stream().mapToInt (i > i).average().parallel();
C. double avg = numbers.stream().average().getAsDouble();
D. double avg = numbers.stream().parallel().averagingDouble(a > a);
E. double avg = numbers.stream().collect(Collectors.averagingDouble(n > n));
Answer: A,C
Explanation: