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FCSS - Enterprise Firewall 7.4 Administrator
- Exam Number/Code : FCSS_EFW_AD-7.4
- Exam Name : FCSS - Enterprise Firewall 7.4 Administrator
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
What is a physical layer (Layer 1) bypass mat allows inline paired IPS interfaces to go into bypass mode so that the hardware forwards packets between the inline port pairs without software intervention?
A. Cluster
B. Fail-To-Wire
C. Redundant interface
D. Tap
E. EtherChannel
Answer: B
NEW QUESTION: 2
On a corporate network, hosts on the same VLAN can communicate with each other, but they are unable to communicate with hosts on different VLANs. What is needed to allow communication between the VLANs?
A. a router with an IP address on the physical interface connected to the switch
B. a router with subinterfaces configured on the physical interface that is connected to the switch
C. a switch with a trunk link that is configured between the switches
D. a switch with an access link that is configured between the switches
Answer: B
Explanation:
Different VLANs can't communicate with each other , they can communicate with the help of Layer3 router. Hence , it is needed to connect a router to a switch , then make the sub-interface on the router to connect to the switch, establishing Trunking links to achieve communications of devices which belong to different VLANs.
When using VLANs in networks that have multiple interconnected switches, you need to use VLAN trunking between the switches. With VLAN trunking, the switches tag each frame sent between switches so that the receiving switch knows to what VLAN the frame belongs. End user devices connect to switch ports that provide simple connectivity to a single VLAN each. The attached devices are unaware of any VLAN structure.
By default, only hosts that are members of the same VLAN can communicate. To change this and allow inter-VLAN communication, you need a router or a layer 3 switch.
Here is the example of configuring the router for inter-vlan communication RouterA(config)#int f0/0.1 RouterA(config-subif)#encapsulation ? dot1Q IEEE 802.1Q Virtual LAN RouterA(config-subif)#encapsulation dot1Q or isl VLAN ID RouterA(config-subif)# ip address x.x.x.x y.y.y.y
NEW QUESTION: 3
Oracleの同義語について正しいのは次の2つです。
A. 同義語は、パッケージ内のオブジェクトに作成できます。
B. すべてのユーザーがPUBLICシノニムを作成できます。
C. すべてのプライベートシノニム名は、データベース内で一意である必要があります。
D. シノニムはシノニムを持つことができます。
E. シノニムにはオブジェクト番号があります。
Answer: A,C