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H3CSE-RS-RT

  • Exam Number/Code : GB0-382
  • Exam Name : H3CSE-RS-RT
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
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NEW QUESTION: 1
You are configuring failover clustering.
You need to install multipath support on the servers.
What should you do?
A. Run the Dism /online /enable-feature: MultipathIo command.
B. Run the mpiocpl.exe command.
C. Run the ocsetup /w MultipathIo command.
D. Run the mpclaim.exe command.
Answer: C
Explanation:
To install MPIO on Server core on Windows Server 2008 run this command from a command prompt
"ocsetup MultipathIo /norestart" and then run " mpclaim -r -i -a "" This command Installs the Microsoft MPIO Optional Component on non Server Core installations and then sets the Microsoft MPIO DSM (MSDSM) to claim all unclaimed Microsoft MPIO devices in the system.
MPCLAIM Command Line Reference:
Usage: mpclaim reboot_option install_switch device_switch device_hwid(s) reboot_option Whether to automatically reboot or not -r automatically reboot without prompting -n suppress reboot request (CALLER IS EXPECTED TO REBOOT) install_switch Whether to add or remove MPIO support -i install MPIO optional component and add multipath support for device -u remove multipath support for device and uninstall MPIO OC if no remaining devices are configured for MPIO device_switch Whether to apply above options to all devices or passed-in devices -d following parameters indicate hardware ids of devices -a work on all applicable devices -c work on only all SPC3-compliant devices (meaningful only in the context of install. If used with '-u', it is treated as '-a') device_hwid HardwareIDs of Devices to be MPIO'd, as strings of vendor8product16, delimited by a space (Note: Use empty string with '-a' option)
http://blogs.msdn.com/b/san/archive/2008/07/27/microsoft-mpio-command-line-reference-mpclaim-andserver-core-configuration.aspx
Wrong answer:
Enable MPIO --> Dism /online /enable-feature:MultipathIo
Important
When using DISM to enable or disable features, the feature name is case-sensitive.
http://technet.microsoft.com/en-us/library/ee619752(v=WS.10).aspx

NEW QUESTION: 2
Which of the following reporting options is least likely with regard to supplementary information that is
required by GAAP?
A. The auditor's report on the financial statements makes no reference to the supplementary information.
B. The auditor's report on the financial statements includes both an opinion on the supplementary
information and a statement restricting the use of the report.
C. The auditor's report on the financial statements includes an opinion regarding whether the
supplementary information is fairly stated in all material respects in relation to the financial statements
taken as a whole.
D. A disclaimer of opinion is issued on supplementary information that is not clearly distinguished from the
financial statements and is not marked "unaudited."
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Choice "C" is correct. There is no requirement that the auditor's report on supplementary information
required by GAAP be restricted.
Choice "A" is incorrect. An auditor is not required to audit supplementary information, and in such cases
the auditor's report on the basic financial statements would not generally include a reference to such
information.
Choice "B" is incorrect. When supplementary information that is not clearly distinguished from the financial
statements is not marked "unaudited," the auditor would generally issue a disclaimer on that information.
Choice "D" is incorrect. When the auditor chooses to apply auditing procedures to the supplementary
information, he or she may express an opinion regarding whether the supplementary information is fairly
stated in all material respects in relation to the financial statements taken as a whole.

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <iostream>
# include <set>
# include <vector>
using namespace std;
int main(){
int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<int>v(myints, myints+10);
set<int> s1(v.begin(),v.end());
set<int, greater<int> > s2(v.begin(), v.end());
for(set<int>::iterator i=s1.begin();i!= s1.end(); i++) {
cout<<*i<<" ";
}
for(set<int, greater<int> >::iterator i=s2.begin();i!= s2.end(); i++) { cout<<*i<<" ";
}
cout<<endl;
return 0;
}
A. program outputs: 9 8 7 6 5 4 3 2 1 0 0 1 2 3 4 5 6 7 8 9
B. program outputs: 9 8 7 6 5 4 3 2 1 0 9 8 7 6 5 4 3 2 1 0
C. program outputs: 0 1 2 3 4 5 6 7 8 9 9 8 7 6 5 4 3 2 1 0
D. program outputs: 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9
Answer: C