H13-625_V1.0 Latest Test Format & H13-625_V1.0 Valid Exam Registration - HCIP-Storage Solution Architect V1.0 Study Guides - Assogba
HCIP-Storage Solution Architect V1.0
- Exam Number/Code : H13-625_V1.0
- Exam Name : HCIP-Storage Solution Architect V1.0
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
Identify two settings in the Authentication Scheme definition of Oracle Access Manager 11g.
A. Error
B. Authentication Password
C. Challenge Method
D. Level
Answer: B,D
NEW QUESTION: 2
You are developing a Windows Communication Foundation (WCF) service that does not operate on a duplex channel.
You find that operations do not start until all previous operations have finished. The service hosting code contains the following lines.
var service = new WarehouseService();
var host = new ServiceHost(service);
You need to ensure that new operations do not wait for previous operations to finish.
Which attribute should you use to decorate the service?
A. [ServiceBehavior(
InstanceContextMode = InstanceContextMode.Single,
ConcurrencyMode = ConcurrencyMode.Single) ]
B. [CallbackBehavior(
ConcurrencyMode = ConcurrencyMode.Multiple) ]
C. [ServiceBehavior(
InstanceContextMode = InstanceContextMode.Single,
ConcurrencyMode = ConcurrencyMode.Multiple)]
D. [ServiceBehavior(
InstanceContextMode = InstanceContextMode.Single,
ConcurrencyMode = ConcurrencyMode.Reentrant) ]
Answer: C
Explanation:
Only ConcurrencyMode.Multiple gives as singleton service with support of multiple requests
NEW QUESTION: 3
엔터티 수준 제어의 효과를 테스트 할 때 사용되는 구조화 된 인터뷰와 비교하여 촉진 된 워크샵의 추가 이점은 무엇입니까?
A. 촉진 된 워크숍에서 얻은 증언 증거는 일반적으로 더 신뢰할 수 있는 것으로 간주됩니다.
B. 워크숍을 진행하는 동안 사람들은 비공개 인터뷰보다 내부 감사 자에게 더 공개적으로 이야기 합니다.
C. 내부 감사자는 워크숍을 진행하는 동안 수집 된 데이터로 충분하므로 다른 정보 소스가 필요하지 않습니다.
D. 촉진 된 워크숍은 동일한 문제에 대해 여러 관점을 가져올 수 있는 토론의 시너지 효과를 창출합니다.
Answer: D
NEW QUESTION: 4
All equipment is operational. Through which two methods can a wireless client receive an IP address when associating to the WLAN? (Choose two.)
A. The clients can receive an IP address from SW1.
B. The clients can use a static IP address.
C. The clients can receive an IP address in a round-robin maner from either SW1 or WLC1.
D. The clients will not receive an IP address from either DHCP server because of overlapping address ranges.
E. Tie clients can receive an IP address from WLC1.
Answer: B,E
Explanation:
Explanation/Reference:
Explanation:
As shown be,ow, the DHCP server functionality has been enabled on the WLC1. Aside from DHCP, all clients can always statically assign themselves an IP address.