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SAP Certified Associate - Implementation Consultant - SAP Service Cloud
- Exam Number/Code : C_C4H51_2405
- Exam Name : SAP Certified Associate - Implementation Consultant - SAP Service Cloud
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
You have an Azure subscription that contains 100 virtual machines. You regularly create and delete virtual machines. You need to identify unattached disks that can be deleted. What should you do?
A. From Azure Cost Management, open the Optimizer tab and create a report.
B. From Microsoft Azure Storage Explorer, view the Account Management properties.
C. From Azure Cost Management create a Cost Management report.
D. From the Azure portal, configure the Advisor recommendations.
Answer: B
Explanation:
You can find unused disks in the Azure Storage Explorer console. Once you drill down to the Blob containers under a storage account, you can see the lease state of the residing VHD (the lease state determines if the VHD is being used by any resource) and the VM to which it is leased out. If you find that the lease state and the VM fields are blank, it means that the VHD in question is unused.
Note: The ManagedBy property stores the Id of the VM to which Managed Disk is attached to. If the ManagedBy property is $null then it means that the Managed Disk is not attached to a VM
References:
https://cloud.netapp.com/blog/reduce-azure-storage-costs
NEW QUESTION: 2
Sie verwenden den Azure-Tabellenspeicher, um Kundeninformationen für eine Anwendung zu speichern. Die Daten enthalten Kundendaten und sind nach Nachnamen unterteilt. Sie müssen eine Abfrage erstellen, die alle Kunden mit dem Nachnamen Smith zurückgibt. Welches Codesegment sollten Sie verwenden?
A. TableQuery.GenerateFilterCondition ("LastName", QueryComparisons.Equal, "Smith")
B. TableQuery.GenerateFilterCondition ("PartitionKey", QueryComparisons.Equal, "Smith")
C. TableQuery.GenerateFilterCondition ("LastName", Equals, "Smith")
D. TableQuery.GenerateFilterCondition ("PartitionKey", Equals, "Smith")
Answer: B
Explanation:
Erläuterung:
Ruft alle Entitäten in einer Partition ab. Das folgende Codebeispiel gibt einen Filter für Entitäten an, bei denen 'Smith' der Partitionsschlüssel ist. In diesem Beispiel werden die Felder der einzelnen Entitäten in den Abfrageergebnissen an die Konsole ausgegeben.
Erstellen Sie die Abfrageoperation für alle Kundenentitäten, für die PartitionKey = "Smith" ist.
TableQuery <CustomerEntity> query = new TableQuery <CustomerEntity> (). Where (TableQuery.GenerateFilterCondition ("PartitionKey", QueryComparisons.Equal, "Smith")); Verweise:
https://docs.microsoft.com/de-de/azure/cosmos-db/table-storage-how-to-use-dotnet
NEW QUESTION: 3
単一のJMSアクティベーション仕様は、次のどれに適用できますか?
A. 1つのメッセージ駆動型Beanのみ
B. EJB 3.0 Beanのみ
C. 単一バス
D. 1つ以上のメッセージ駆動型Bean
Answer: D