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HCIP-Cloud Computing Solution Architect V1.0

  • Exam Number/Code : H13-528_V1.0
  • Exam Name : HCIP-Cloud Computing Solution Architect V1.0
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
Where in the controller would we configure a wireless network NOT to use encryption?
A. VAP profile
B. Ratio profile
C. ARM profile
D. AAAprofile
E. SSID profile
Answer: E

NEW QUESTION: 2
パブリックサブネットで手動でNAT AMIを起動します。ネットワークが正しく設定されています。セキュリティグループとネットワークアクセス制御リストは正しく設定されています。プライベートサブネット内のインスタンスはNATにアクセスできます。 NATはインターネットにアクセスできます。ただし、プライベートインスタンスはインターネットにアクセスできません。プライベートインスタンスからのアクセスを許可するために必要な追加の手順は何ですか?
A. プライベートインスタンスの送信元/送信先チェックを無効にします
B. NATインスタンスの送信元/宛先チェックを無効にします
C. プライベートインスタンスの送信元/送信先チェックを有効にします
D. NATインスタンスの送信元/宛先チェックを有効にします
Answer: B

NEW QUESTION: 3
How will the following command change the datalv logical volume?
chlv -e m datalv
A. The logical volume will have new logical partitions spread across as few disks as possible.
B. The logical volume will be rebalanced across the minimum number of physical volumes immediately
C. The logical volumewill be rebalanced across the maximum physical volumes immediately.
D. The logical volume will be encrypted with the key in a file named "m".
Answer: A

NEW QUESTION: 4
Refer to the exhibit:

The box plot was used to analyze daily sales data following three different ad campaigns.
The business analyst concludes that one of the assumptions of ANOVA was violated.
Which assumption has been violated and why?
A. Normality, because Prob > F < .0001.
B. Constant variance, because Prob > F < .0001.
C. Constant variance, because the interquartile ranges are different in different ad campaigns.
D. Normality, because the interquartile ranges are different in different ad campaigns.
Answer: C