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NEW QUESTION: 1
You have two databases with the following settings:

You run the following Transact -SQL statements:

You need to select data from DiskTable and insert the data into MemTable. You must complete the insertion operation into MemTable as an explicit transaction without immediate durability.
Which four Transact-SQL segments should you use? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the answer area and arrange them in the correct order.

Answer:
Explanation:

Explanation

Box 1: BEGIN TRANSACTION
Box 2: UPDATE ... #Disktable
Box 3: IF... SELECT INTO ...#Disktable
Box 4: .. DELAYED_DURABILITY = ON
The COMMIT syntax is extended so you can force delayed transaction durability. If DELAYED_DURABILITY is DISABLED or FORCED at the database level (see above) this COMMIT option is ignored.
Syntax:
COMMIT [ { TRAN | TRANSACTION } ] [ transaction_name | @tran_name_variable ] ] [ WITH ( DELAYED_DURABILITY = { OFF | ON } ) ] References:
https://docs.microsoft.com/en-us/sql/relational-databases/logs/control-transaction-durability?view=sql-server-20

NEW QUESTION: 2
NIST Special Publication 800-50 is a security awareness program. It is designed for those people who are currently working in the information technology field and want information on security policies. Which of the following are some of its critical steps? Each correct answer represents a complete solution. Choose two.
A. Awareness and Training Material Development
B. Awareness and Training Material Effectiveness
C. Awareness and Training Material Implementation
D. Awareness and Training Program Design
Answer: A,D

NEW QUESTION: 3
You have two lists of values to correlate.

Which query lists all names in colors1 and how many total matches are there in colors2?
A. SELECTcolors1. Name count (colors2.name)
FROMcolors1
INNER JOINcolors2
oncolors1. Name =colors2.Name
GROUPBYcolors1 .name;
B. SELECTcolors1.name, count(colorse2. Name)
FROMcolorse1 .name =colors2.name
WHEREcolors1. Name =colors2.name
GROUPBYcolors1.name,
C. SELECT colors1 .name.count (colors2.name)
FROMcolors1.Colors2
WHERE
Colors1. Name = (SELECTDISTINCTname FROMcolors2WHERE colors1.name=colors2.name)
GROUPBYcolorse1.name,
D. SELECTcolors1.name, count (colors2.name)
FROMJOINcolors2
oncolors1.name =colors2.name
GROUPBYcolors1.name;
SELECTcolors1.name, count (colors2.name)
FROMcolors1
RIGHTJOIN colors1
oncolors1 .name =colors2.name
GROUP BY colors1.name;
Answer: D