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NEW QUESTION: 1
Which of the following is not a prohibited practice for a broker-dealer?
A. recommending a security to a new client without first ascertaining that client's level of risk tolerance
B. executing a trade for an account holder based on instructions from the account holder's spouse
C. requiring that a client who is engaged in margin transactions leave the securities with the broker-dealer
in "street name"
D. waiting 36 hours before mailing a check after receiving a request for a cash withdrawal from a client if
the client has that much cash available in his account
Answer: C
Explanation:
It is not prohibited for a broker-dealer to require that a client who is engaging in margin
transactions to leave the securities with the broker in "street name." This is the normal business practice.
A margin transaction means that the client is borrowing part of the funds he's investing, and the securities
are serving as collateral for the loan. It is illegal to delay sending a check upon receiving a request for a
cash withdrawal, assuming the client has the cash available in his account; to recommend a security to a
client without knowing anything about him, including his tolerance for risk; and to execute a trade on
instructions from anyone other than the account holder unless that party has at least limited power of
attorney.

NEW QUESTION: 2
Drag and Drop Question
Drag and drop the IPv4 network subnets from the left onto the correct usable host ranges on the right

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 3
An administrator is required to configure a policy in Cisco UCS to schedule backups. Which two backup types can be scheduled? (Choose two.)
A. system configuration
B. all configuration
C. logical configuration
D. import configuration
E. full state
Answer: A,B