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Oracle Payroll Cloud 2023 Implementation Professional

  • Exam Number/Code : 1Z0-1050-23
  • Exam Name : Oracle Payroll Cloud 2023 Implementation Professional
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
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NEW QUESTION: 1
A company wants to configure BGP on a router so that other BGP neighbors cannot influence the path of a particular route .which action must be taken to accomplish this configuration ?
A. Configure a low router ID for the route
B. Configure a high local preference for the route
C. Configure a low MED for the route
D. Configure a high weight for the route
Answer: B

NEW QUESTION: 2
Which switch would STP choose to become the root bridge in the selection process?
A. 32768: 22-33-44-55-66-77
B. 32769: 22-33-44-55-66-78
C. 32768: 11-22-33-44-55-66
D. 32769: 11-22-33-44-55-65
Answer: C
Explanation:
The root bridge of the spanning tree is the bridge with the smallest (lowest) bridge ID. Each bridge has a configurable
priority number and a MAC Address; the bridge ID contains both numbers combined together - Bridge priority + MAC
(32768.0200.0000.1111). The Bridge priority default is 32768 and can only be configured in multiples of
4096(Spanning tree uses the 12 bits extended system ID). To compare two bridge IDs, the priority is compared first, as
if looking at a real number anything less than 32768...will become the target of being the root. If two bridges have
equal priority then the MAC addresses are compared; for example, if switches A (MAC=0200.0000.1111) and B
(MAC=0200.0000.2222) both have a priority of 32768 then switch A will be selected as the root bridge.
In this case, 32768: 11-22-33-44-55-66 would be the bridge because it has a lower priority and MAC address.

NEW QUESTION: 3
チームメンバーは必要な時間働いていますが、不十分な出力を提供しています。プロジェクトマネージャーは最初に何をすべきですか?
A. 作業を行わなかった場合の結果についてチームメンバーにアドバイスします。
B. チームメンバーと会って、パフォーマンスが低下する理由を特定します。
C. チームメンバーの作業の一部を他のチームメンバーに割り当てます
D. チームメンバーのパフォーマンスが低いことを人事部門に通知します。
Answer: B

NEW QUESTION: 4
Examine this code:

The anonymous block fails with:
ERROR at line 1:
ORA-01403: no data found
ORA-06512: at line 5
Which two are valid options to prevent this error from occurring?
A. pdatabuf (1) := NULL; should be added after line 4.
B. Line 5 should be replaced with:DBMS_LOB.CREATETEMPORARY (pdatabuf (1), TRUE, DBMS_LOB.CALL);
C. Rewrite the block as:DECLARETYPE databuf_arr IS TABLE OF CLOB INDEX BY BINATY_INTEGER;pdatabuf databuf_arr;PROCEDURE mytemplob (x OUT CLOB) ISBEGINDBMS_LOB.CREATETEMPORARY (x, TRUE, DBMS_LOB, SESSION);END;BEGINmytemplob (pdatabuf (1));END;/
D. Line 5 should be replaced with:DBMS_LOB.CREATETEMPORARY (pdatabuf, TRUE, DBMS_LOB.SESSION);
E. Line 5 should be replaced with:DBMS_LOB.CREATETEMPORARY (pdatabuf (1), FALSE, DBMS_LOB.SESSION);
Answer: C,D