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SAP Certified Associate - Implementation Consultant - SAP SuccessFactors Onboarding
- Exam Number/Code : C-THR97-2505
- Exam Name : SAP Certified Associate - Implementation Consultant - SAP SuccessFactors Onboarding
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
You have a Microsoft Azure Active Directory (Azure AD) tenant that contains the users shown in the following table.
Your company uses Windows Defender Advanced Threat Protection (ATP). Windows Defender ATP contains the roles shown in the following table.
Windows Defender ATP contains the device groups shown in the following table.
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation
NEW QUESTION: 2
ライトウェイトディレクトリアクセスプロトコル(LDAP)環境では、ディレクトリサーバーの各エントリは___________によって識別されます。
A. ドメイン名(DN)
B. 識別名(DN)
C. デフォルト名(DN)
D. ディレクトリ名(DN)
Answer: B
NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:
You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct L WHERE D.CustNo = L.CustNo
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
Answer: A
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
NEW QUESTION: 4
Exhibit A is an example of which of the following types of Sequence Activities?
A. Mathematical analysis diagramming
B. Precedence diagramming
C. Activity-on-arrow diagramming
D. Project schedule network diagramming
Answer: B