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NEW QUESTION: 1
The joint probability of events A and B occurring equals 0.11. The probability of neither A nor B occurring equals 0.64. If P(A) equals 0.24, the probability of B occurring equals ________.
A. 0.51
B. 0.46
C. 0.29
D. 0.23
Answer: D
Explanation:
Explanation/Reference:
Explanation:
We are given that P(neither A nor B) = 0.64, P(A and B) = 0.11 and P(A) = 0.24. The probability of neither A nor B occurring equals one minus the probability of either A or B occurring i.e. P(neither A nor B) = 1 - P (A or B).
Thus, P(A or B) = 1 - P(neither A nor B) = 1 - 0.64 = 0.36.
Now, P(A or B) = P(A) + P(B) - P(A and B)
Therefore, P(B) = P(A or B) - P(A) + P(A and B) = 0.36 - 0.24 + 0.11 = 0.23.

NEW QUESTION: 2
HOTSPOT
Your network contains an Active Director domain named contoso.com. The domain contains a file server named Server1. All servers run Windows Server 2012 R2.
You have two user accounts named User1 and User2. User1 and User2 are the members of a group named Group1. User1 has the Department value set to Accounting, user2 has the Department value set to Marketing. Both users have the Employee Type value set to Contract Employee.
You create the auditing entry as shown in the exhibit. (Click the Exhibit button.)

Use the drop-down menus to select the answer choice that completes each statement based on the information presented in the graphic.
Note: Each correct selection is worth one point.
Hot Area:

Answer:
Explanation:

NEW QUESTION: 3
疑わしいパスワード変更のセキュリティイベントが発生した場合、PTAはどのタイプの自動修復を実行できますか？
A. パスワードの変更
B. セッションの終了
C. パスワードの調整
D. セッションの一時停止
Answer: C