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SAP Certified Associate - Business Process Integration with SAP S/4HANA

  • Exam Number/Code : C-TS410-2504
  • Exam Name : SAP Certified Associate - Business Process Integration with SAP S/4HANA
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
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NEW QUESTION: 1
Which of the following statements are correct about the circuit breaker? (Multiple Choice)
A. Do not use a leakage protection circuit breaker in the front of the UPS.
B. The circuit breakers provide both disconnecting and protection functions in the system.
C. The disconnecting switch plays the same effect as the circuit breaker in the UPS.
D. There is no need to consider redundancy in circuit breaker selection.
Answer: A,B

NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten die folgenden Spalten:

Sie müssen eine Abfrage ausführen, um die Gesamtzahl der Kunden zu ermitteln, die sowohl Einzahlungs- als auch Darlehenskonten haben.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
B. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
C. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
G. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: C
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 3
Which structure records are stored in the private region?(Each correct answer presents part of the solution. Select three.)
A. Disk group kernel log
B. Disk group configuration
C. File system metadata
D. Partition tables
E. Disk and disk group ID
Answer: A,B,E
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 4
Which of the following find commands will print out a list of files owned by root and with the SUID bit set in / usr?
A. find /usr -ls \*s\* -u root
B. find /usr -uid 0 -perm +4000
C. find /usr -suid -perm +4000
D. find -type suid -username root -d /usr
E. find -user root +mode +s /usr
Answer: B