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Microsoft Information Protection Administrator
- Exam Number/Code : SC-400
- Exam Name : Microsoft Information Protection Administrator
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
- Price:
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NEW QUESTION: 1
You create an application that uses features from both XNA and Microsoft Silverlight.
Which file in Microsoft Visual Basic .NET is specifically created by the Windows Phone Silverlight and XNA application template for your XNA code?
A. MainPage.xaml.vb
B. AppServiceProvider.vb
C. GamePage.xaml.vb
D. App.xaml.vb
Answer: C
NEW QUESTION: 2
Which two of the following are Seven Waste's of Software Development? (Choose two.)
A. Process Integration
B. Extra features
C. Path Analysis
D. Task Switching
Answer: B,D
NEW QUESTION: 3
Which Application Development Cloud Platform Service can be used for running Java EE applications?
A. Oracle Application Hub Cloud Service
B. Oracle Developer Cloud Service
C. Oracle Java Cloud Service
D. Oracle Integration Cloud Service
Answer: C
Explanation:
Explanation/Reference:
Reference: https://www.oracle.com/assets/java-ee-apps-on-java-cloud-2360601.pdf
NEW QUESTION: 4
Your database contains tables named Products and ProductsPriceLog. The Products table contains columns named ProductCode and Price. The ProductsPriceLog table contains columns named ProductCode, OldPrice, and NewPrice.
The ProductsPriceLog table stores the previous price in the OldPrice column and the new price in the NewPrice column.
You need to increase the values in the Price column of all products in the Products table by 5 percent. You also need to log the changes to the ProductsPriceLog table.
Which Transact-SQL query should you use?
A. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, deleted.Price, inserted.Price * 1.05
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
B. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, deleted.Price, inserted.Price
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
C. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, inserted.Price, deleted.Price
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
D. UPDATE Products SET Price = Price * 1.05
INSERT INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
SELECT ProductCode, Price, Price * 1.05 FROM Products
Answer: B
Explanation:
Explanation/Reference:
Reference: http://msdn.microsoft.com/en-us/library/ms177564.aspx