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OMG-Certified Expert in BPM 2 - Fundamental
- Exam Number/Code : OMG-OCEB2-FUND100
- Exam Name : OMG-Certified Expert in BPM 2 - Fundamental
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
Which label is advertised by an LSR to inform neighboring LSRs to perform the penultimate hop popping operation?
A. push
B. php
C. 0x00
D. imp-null
E. swap
Answer: D
Explanation:
Penultimate hop popping (PHP) is a function performed by certain routers in an MPLS enabled network. It refers to the process whereby the outermost label of an MPLS tagged packet is removed by a Label Switch Router (LSR) before the packet is passed to an adjacent Label Edge Router (LER).
NEW QUESTION: 2
A. Option C
B. Option B
C. Option E
D. Option D
E. Option A
Answer: E
NEW QUESTION: 3
The Quality Assurance team is testing a new third party developed application. The Quality team does not have any experience with the application. Which of the following is the team performing?
A. Penetration testing
B. White box testing
C. Grey box testing
D. Black box testing
Answer: D
Explanation:
Black-box testing is a method of software testing that examines the functionality of an application without peering into its internal structures or workings. This method of test can be applied to virtually every level of software testing: unit, integration, system and acceptance. It typically comprises most if not all higher level testing, but can also dominate unit testing as well.
Specific knowledge of the application's code/internal structure and programming knowledge in general is not required. The tester is aware of what the software is supposed to do but is not aware of how it does it. For instance, the tester is aware that a particular input returns a certain, invariable output but is not aware of how the software produces the output in the first place.
NEW QUESTION: 4
あなたは、ContosoDbという名のMicrosoft SQL Server 2012データベースを管理します。展示に示すように、テーブルが定義されます。(Exhibitボタンをクリックしてください。)
あなたは、CustomerId価値を以下のXMLフォーマットで1をつけておいているCustomers列のために注文テーブルから列を示す必要があります。
どのTransact-SQLクエリを使うべきでしょうか。
A. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
C. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
H. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
Answer: G
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms188273.aspx