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NEW QUESTION: 1
This question requires that you evaluate the underlined text to determine if it is correct.
You need to know of any service interruptions for Microsoft Intune. You should check the Microsoft Intune Service Dashboard.
Instructions: Review the underlined text. If it makes the statement correct, select "No change is needed." If the statement is incorrect, select the answer choice that makes the statement correct.
A. Microsoft Connectivity Analyzer Tool
B. remote connectivity analyzer
C. No change is needed
D. Service Health Dashboard
Answer: C
Explanation:
Explanation
References:
https://www.itprotoday.com/cloud-computing/tip-microsoft-intune-service-dashboard

NEW QUESTION: 2
開発チームは、AWS Elastic Beanstalkを使用して、ロードバランシングされたWeb層とAmazon RDSデータベース層で構成される2層アプリケーションを本番環境にデプロイしています。チームはRDSインスタンスをElastic Beanstalkから分離したいと考えています。
どうすればこれを達成できますか？
A. Amazon RDSなしで新しいElastic Beanstalk環境を再作成します。
B. データベースの関連付けを解除するように展開ポリシーを変更します。
C. AWS CLIを使用してデータベースとの関連付けを解除します。
D. Elastic Beanstalk CLIを使用してデータベースとの関連付けを解除します。
Answer: B

NEW QUESTION: 3
Refer to the exhibit.

Which type of ACL is shown in this configuration?
A. IPv6
B. unified
C. IPv4
D. IDFW
Answer: B

NEW QUESTION: 4
学生の年半ば成績を記録するためにStudentCode、SubjectCodeおよび成績カラムを持っているテーブルを作成します。 テーブルには様々な主題のために50人の学生によって得られたマークがあります。あなたは、マークと一緒に、各被験者の最高点を獲得した学生を取得する必要があります。どのTransact-SQLクエリを使うべきでしょうか。
A. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
C. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
G. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: C