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NEW QUESTION: 1
Refer to the exhibit.

A VNX Snapshot is started on a thick LUN at 09:37. The customer notices that throughput declines after 09:49 or so. They want to know how Primary LUN throughput will decrease further over time.
What should be your explanation?
A. Pool disk sizes and thick LUN compression ratios will set the lower performance bound.
B. The VNX Snapshot read/write ratio and IO size will determine primary LUN performance level.
C. The number and type of Reserved LUNs will determine the lower limit of Primary LUN performance.
D. Primary LUN throughput will decrease until it reaches thin LUN performance levels.
Answer: D

NEW QUESTION: 2

A. Option D
B. Option B
C. Option A
D. Option C
Answer: B

NEW QUESTION: 3
Note: This question is part of a series of questions that present the same scenario. Each question
in the series contains a unique solution that might meet the stated goals. Some question sets
might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these
questions will not appear in the review screen.
Your network contains an Active Directory forest.
You deploy Microsoft 365.
You plan to implement directory synchronization.
You need to recommend a security solution for the synchronized identities. The solution must meet the
following requirements:
Users must be able to authenticate successfully to Microsoft 365 services if Active Directory becomes

unavailable.
Users passwords must be 10 characters or more.

Solution: Implement password hash synchronization and configure password protection in the Azure AD
tenant.
Does this meet the goal?
A. No
B. Yes
Answer: A

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <deque>
#include <vector>
#include <iostream>
#include <string>
using namespace std;
template<typename T>
void print(T start, T end)
{
while (start != end)
cout<<*start++;
}
int main ()
{
string t[] = {"one", "two" ,"three" ,"four", "five"};
vector<string>v1(t, t+5);
deque<string>d1(v1.rbegin(), v1.rend());
d1.push_back("zero");
print(d1[0].rbegin(),d1[0].rend());
return 0;
}
A. program outputs: orez
B. compilation error
C. program outputs: evif
D. program outputs: five
Answer: C