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SAP Certified Associate - Implementation Consultant - SAP S/4HANA Cloud Public Edition, Financial Accounting

  • Exam Number/Code : C-S4CFI-2408
  • Exam Name : SAP Certified Associate - Implementation Consultant - SAP S/4HANA Cloud Public Edition, Financial Accounting
  • Questions and Answers : 213 Q&As
  • Update Time: 2019-01-10
  • Price: $ 99.00 $ 39.00

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NEW QUESTION: 1
What is a basic assumption for an architect using the HPE Servers TCO calculator to justify a customer's migration away from a fully depreciated set of hardware?
A. When the customer's older systems are under a support contract, a new system can sometimes pay for itself simply by not renewing the older support contracts.
B. The Net Present Value (NPV) is the difference between the value of the older systems and the cost of the new systems.
C. The opportunity costs of not migrating from a legacy environment to an HPE Converged
Infrastructure Solution, in terms of IT Efficiency and User Productivity, will always justify the purchase.
D. By analyzing the project's internal rate of return (IRR), it is possible to determine if the lower IRR will make it more desirable to undertake the project.
Answer: B

NEW QUESTION: 2
Which MSC link type (i.e. MSPLINK TYPE=) uses the IMS Connect feature to send and receivemessages
in the network?
A. MTM
B. VTAM
C. TCPIP
D. CTC
Answer: C

NEW QUESTION: 3
Given:

You wants to make the reduction operation parallelized.
Which two modifications will accomplish this?
A. Replace line 1with int sum = number. Stream ( ) . flatMap (a -> a) .reduce (0, (n, m) -> n +m );
B. Replace line 1 with int sum = numbers. Parallel ( ). Stream ( ). Reduce (0, (n, m ) -> n + m);
C. Replace line 1 with int sum = numbers. Stream (). Interate (0, a -> a+1. Reduce (0, (n m) -> n+m);
D. Replace line 1with int sum = number.stream. parallel ( ). Reduce (0, (n, m) -> n + m);
E. Replace line 1with int sum = numbers. ParallelStream ( ). Reduce (0, (n, m ) -> n + m);
Answer: A,C

NEW QUESTION: 4
View the Exhibit button and examine the structures of ORDERS and ORDER_ITEMS tables.
In the ORDERS table, ORDER_ID is the PRIMARY KEY and in the ORDER_ITEMS table, ORDER_ID and LINE_ITEM_ID form the composite primary key.
Which view can have all the DML operations performed on it?

A. CREATE VIEW V4(or_no, or_date, cust_id)
AS SELECT order_id, order_date, customer_id
FROM orders
WHERE order_date < 30-mar-2007'
WITH CHECK OPTION;
B. CREATE VIEW V2
AS SELECT order_id, line_item_id, unit_price*quantity total
FROM order items;
C. CREATE VIEW V1
AS SELECT order_id, product_id
FROM order_items;
D. CREATE VIEW V3
AS SELECT o.order_id, o.customer_id, i.product_id
FROM orders o, order_items i
WHERE o.order_id=i. order_id;
Answer: A