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Certified Ethical Hacker Exam (CEHv13)
- Exam Number/Code : 312-50v13
- Exam Name : Certified Ethical Hacker Exam (CEHv13)
- Questions and Answers : 213 Q&As
- Update Time: 2019-01-10
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NEW QUESTION: 1
How can the default route be generated? (Choose all that apply.)
A. Generated by dynamic routing protocols.
B. Manually configured.
C. Generated by link layer protocols.
D. Automatically generated by the router.
Answer: A,B
NEW QUESTION: 2
A customer is looking for two new SAN Switches. A Business Partner suggested the Cisco MDS 9148 or IBM SAN48B-5.
Which key differencebetween these products should the storage specialist discuss with the customer?
A. Cisco MDS 9148 supports USB for microcode upgradability
B. IBM SAN48B-5 switches offer "ports on demand" scalability
C. IBM SAN48B-5 supports optional 16 Gbps SFP+ connections
D. Cisco MDS 9148 supports FICON attachement
Answer: C
NEW QUESTION: 3
ユーザーがMS SQL RDSデータベースサーバーでマルチAZ機能を有効にしました。
ユーザーがマルチAZ機能をよりよく理解するのに役立つのは、以下のステートメントのどれですか。
A. マルチAZでは、AWSはDBを1つだけ実行しますが、データをスタンバイレプリカに同期的にコピーします
B. マルチAZでは、AWSは2つのDBを並行して実行し、データをレプリカコピーに同期的にコピーします
C. AWS MS SQLはマルチAZ機能をサポートしていません
D. マルチAZでは、AWSは2つのDBを並行して実行し、データをレプリカコピーに非同期的にコピーします
Answer: A
Explanation:
Amazon RDS provides high availability and failover support for DB instances using Multi-AZ deployments. In a Multi-AZ deployment, Amazon RDS automatically provisions and maintains a synchronous standby replica in a different Availability Zone. The primary DB instance is synchronously replicated across Availability Zones to a standby replica to provide data redundancy, eliminate I/O freezes, and minimize latency spikes during system backups. Running a DB instance with high availability can enhance availability during planned system maintenance, and help protect your databases against DB instance failure and Availability Zone disruption.Note that the high-availability feature is not a scaling solution for read-only scenarios; you cannot use a standby replica to serve read traffic. To service read-only traffic, you should use a read replica.
NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:
You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
Answer: A
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php